试题详情

在SQL Server中,下面T-SQL代码运行完的结果是()_x000D_ declare @counter int_x000D_ set @counter=1_x000D_ while @counter<3_x000D_ begin_x000D_ set @counter=@counter+1_x000D_ print @counter_x000D_ break_x000D_ print ‘loop’_x000D_ end

A2 loop

B2

C2 loop 3 loop

D2 3