试题详情

精密称取氯化钠0.1250g,用0.1011mol/L的硝酸银滴定至终点,消耗21.02ml[已知1ml硝酸银滴定液(0.1mol/L)相当于NaC15.844mg],则氯化钠的百分含量为( )

A99.95%

B99.35%

C100%

D98.35%

E99.99%